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7x^2+32x-92=0
a = 7; b = 32; c = -92;
Δ = b2-4ac
Δ = 322-4·7·(-92)
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3600}=60$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-60}{2*7}=\frac{-92}{14} =-6+4/7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+60}{2*7}=\frac{28}{14} =2 $
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